Elevator Mechanic Practice Exam

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Prepare for your Elevator Mechanic Exam with comprehensive quizzes, flashcards, and multiple-choice questions that cover all essential topics. Boost your knowledge and confidence as you get ready for your certification!

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You need to replace an unmarked SINGLE PHASE transformer with primary voltage at 220vac current at 5amp. What size would you need to double it?

1.5 kVa
2.2 kVa
2.8 kVa
3.5 kVa

The correct answer is: 1.5 kVa

To determine the appropriate size of a transformer based on the given parameters, it is essential to understand the relationship between voltage, current, and apparent power, which is measured in kilovolt-amperes (kVA). The formula to calculate the apparent power (kVA) is: \[ \text{kVA} = \frac{\text{Voltage (V)} \times \text{Current (A)}}{1000} \] Given the primary voltage of 220 VAC and a current of 5 A, we can substitute these values into the formula: \[ \text{kVA} = \frac{220 \, \text{V} \times 5 \, \text{A}}{1000} \] Calculating that gives: \[ \text{kVA} = \frac{1100}{1000} = 1.1 \, \text{kVA} \] If you need to double the kVA, you would multiply 1.1 kVA by 2: \[ 1.1 \times 2 = 2.2 \, \text{kVA} \] Therefore, it makes sense that the appropriate transformer size to accommodate this doubling of the load would be 2.